Click,Click,ClickClickClicl,Click,Click,Click

Except that Magnum's hill is nowhere near 45 degrees.

Funny...in the off-season here in Los Angeles I ride coasters ;) Knotts had park-wide ERT-like conditions last Friday!

mOOSH

Moosh...when ya coming back to Chicago? 'Cause when ya do, you'll get a swift kick in the arse buddy-boy. ;) ;)

LOL...maybe later this year.

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Mamoosh said:
Funny...in the off-season here in Los Angeles I ride coasters Knotts had park-wide ERT-like conditions last Friday!

mOOSH

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Great news Mamie!

I am heading there in two weeks and hopefully t'will be the same.

Don't see why it wouldn't, 'Tuan. You coming for Solace?

OK, these are GUESSTIMATES.....(had a lot of time sitting on the lift of DD waiting for the crew on ICE to dispatch this past weekend)...;)

Anyhow, on to the math: Anti-rollbacks seemed to be spaced between 4-6" apart, so for the sake of this discussion, we'll say 5". Since the listed HEIGHT in rcdb says 125', my programmer Pythagoras tells me that means (at an approximated 40 degree lift angle), the the track LENGTH of the lift is (app.) 195'. At 5" spacing, this gives us a total number of....468 anti-rollbacks...give or take...;)

Wha-ebh-urh!

I just knew it! I should have studied that pythagorean thereom in Geometry class. This is the only case of me trying to use Gemetry since high school!

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rollergator said:

...lbacks seemed to be spaced between 4-6" apart, so for the sake of this discus...

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Oh no - they got Gator too :(

It's just like '28 days later...'

-Jim (worried that next time I ride I'll start countin too ;))

Gemetry... isn't that the study of rocks? No wait.... that's .... never mind. :-P

-Escher

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Mamoosh said:
Funny...in the off-season here in Los Angeles I ride coasters Knotts had park-wide ERT-like conditions last Friday!

mOOSH

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Hmph. You and Gator just DON'T know how lucky you are. How about some of this nice, freezing snow? ;-)

-Tina

hey i wasn't that far off give or take a few hundred. and yes we are turning into geometry zombies. Its obviously from cds. That coaster deprivation syndrome to you. moosh you lucky son of a motherless goat

40 degrees sounds pretty steep for a B&M lift to me. Toboggans with their verticle lifts have either no or an infinite number of anti-rollbacks, at least geometrically, which is it?

boblo....upon further review, we've decided that:

a) you are probably correct about the lift being more "shallow" than 40 degrees....but that would have a relatively minor impact on the track length of the lift...

b) the lift starts several feet above the ground, which helps offset a), and brings us back closer to the original estimate....

c) I probably have too much free time...and...

d) we're at least keeping the ARN&R crew entertained with this (pointless) discussion...this thread is referenced on the left-mand side of the page, under "Math Dorks", or something...:)
*** Edited 2/12/2004 7:50:24 PM UTC by rollergator***

When doing an ESTIMATE, you should never carry more than one significant figure. This makes calculation easier (if you can't do it in your head, you're not estimating), and assigns the proper (minimal) precision to the result. Here's how it's done:

Assumptions:

Lift height = 200ft

Anti-Rollback spacing = 1/0.5ft

Lift angle = 30 degrees (chosen to simplify working with the numbers)

Now, the length of the lift is L = 200ft / sin 30 (the sine of 30 degrees being 0.5 - this is why I chose 30), so the length is 400ft. With an anti-rollback spaced every 0.5 ft, there should be 800 clicks per anti-rollback dog on the train. Let's say that each train has 3 dogs, so that brings the total number of clicks to about 2000.

That took me all of 15 sec to do in my head and I gaurantee the result is no less accurate than the three significant-figure results that you all spent way too much time calculating.

'hammer a 30 degree 200' high lift runs 400' along the ground, the actual length of the track going up the hill is a little over 447' which already introduces a greater than 10% error in your estimate. 8^P

hammer is right. Remembering the 1:2:rt3 ratios of a 30-60-90 triangle the height 1 = 200, length sqrt3 = 346, hypotenuse 2 = 400. A 30 degree lift that runs 400 horizontally would be 231 ft high and 461 ft long.

DOH!!!! My error, make the lift angle 26.565 degrees for one foot of rise for every two feet of travel along the ground footprint................I've got to stop bouncing my head on the ground.

Get a better helmet? ;)

See ya soon Mike! :)