No....it's TTD!

Tuesday, April 8, 2003 11:13 AM
Worlds fastest elevator......

http://www.reuters.com/newsArticle.jhtml?type=oddlyEnoughNews&storyID=2528716

wonder what TTD's km/min rate is.....

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Tuesday, April 8, 2003 11:21 AM
I wish TTD had the same restraints as the elevator...

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A day is a drop of water in the ocean of eternity. A week is seven drops.

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Tuesday, April 8, 2003 11:25 AM
Hmmm, it'll probably get to the top is just a couple seconds. It's been a while since I was in a physics class...something about 1 m/s per s or something like that. Figure in 120mph and 420'. Anyway, if it climbs 420' in a 2-3 seconds, and there are 13 420's in a mile or something like that, 13 x 3 = 39 seconds. Then again, it was a km per minute so multiply x .6 and you got yer answer!! ;)

So 23 and a half seconds per km? Does that sound right?

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"Know thyself!"
*** This post was edited by janfrederick 4/8/2003 3:31:22 PM ***

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Tuesday, April 8, 2003 11:33 AM
Just doing some quick numbers....
420ft = .128km
2 seconds = .03333 min

basically....if TTD rose the whole 420' in 2-3 seconds it would be 3.84-2.56 km/min

...a little faster than 1km/min huh?
*** This post was edited by Dale Picolet 4/8/2003 3:37:42 PM ***

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Tuesday, April 8, 2003 11:35 AM
not doing the maths, yea it does sound about right, but what about TTD's actual elevator?

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UK, home to the King of Inverts, Nemesis, and the soon Heir, Inferno

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Tuesday, April 8, 2003 11:46 AM
So I wasn't too far off the mark?

Hey, do you think they'll have seatbelts on the elevator?

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"Know thyself!"

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Tuesday, April 8, 2003 11:56 AM
Did someone forget about the deceleration factor?
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Why?
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Tuesday, April 8, 2003 11:59 AM
I guestimated how long it would take to get to the top and so I guess mine is based on an average. The fastest part of the ride is 120 mph. Multiply by 1.2 for km/h and then divide by 60 for minute.

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"Know thyself!"

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Tuesday, April 8, 2003 12:18 PM

Coaster Art Guy said:
Did someone forget about the deceleration factor?
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Why?

Not really....my math figures an average rate of climb based on a given time. The velocity at any one point isn't considered...just the rate at which the entire climb is made. In other words....at it's fastest velocity it is above 3.84km/min...and at it's slowest it is below 2.56km/min. 120mph directly corresponds to 3.22 km/min. Which should tell us that there is no way TTD will hit its peak quicker than 2 seconds as that calculates to a rate of 3.84km/min. Let's say TTD averaged 1km/min on it's climb...it would then top out at 7.7 seconds. These times of course do not take into account the launch track parallel to the ground, the height of the track at the base of the tower, nor the physics of the curve to vertical. It simply assumes TTD acting like an elevator.
*** This post was edited by Dale Picolet 4/8/2003 4:23:09 PM ***

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Tuesday, April 8, 2003 1:24 PM
Alright, let's get all technical here since we're doing mechanics in physics right now:

Let's assume for a moment that friction and air resistance are arbitrary forces. We are then dealing with an object simply being launched upward. The total distance it must cover is 420 feet, which we have astutely determined is approximately 128 m. We know that it goes at 120 mph, which again, through dimensional analysis...

120 mi 1 hr 5280 ft 1 m

1 hr 3600 s 1 mi 3.281 ft

...comes out to (120x5280) / (3600x3.281) = 633,600 / 11811.6 = 53.64 m/s.

So what we know is that the distance is 128 m, the initial velocity is 53.64 m/s, and g we accept is 9.8 m/s/s. At this point, the problem becomes simple kinematics:

x = vt + (1/2)gt^2 or (1/2)gt^2 + vt - x = 0

In polynomial form, the equation can be very easily solved with the good old TI-83 Graphing Calculator. So first, we substitute in all known values and clean up the equation:

(4.9 m/s/s) t^2 + (53.64 m/s) t - 128 m = 0

Since we know that each unit will inevitably cancel out, and that t is in seconds, units are arbitrary:

4.9 t^2 + 53.64 t - 128 = 0

In polynomial form, this equation can be easily solved using the trusty TI-83 Graphing Calculator. The function's zeroes are at t = -12.96 and t = 2.015. Logic dictates that time cannot possibly be negative, and therefore we see that, in a perfect friction-free situation, a projectile being accelerated upward 420 feet at 120 mph will reach the top of its arc in 2.015 seconds.

Now, we have considered throughout this equation that there is no air resistance and no friction, which is completely false. The truth is, though, that the values are only consequential to real physicists, which we certainly are not. Therefore, let's attribute approximately one to two seconds (which is a gross overestimate to begin with) based on the car's friction with the track, the resistance of air, and the fact that, in a non-vacuum situation, the car's mass affects its acceleration.

Therefore, we can conclude that TTD's train will reach the apex of its 420-foot structure somewhere between 3 and 4 seconds after it begins its vertical ascent.

B for the year, my *ss...eat it, Mrs. Yates! :-P

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[Nitro Dave -- 135 Laps] [Track Record: 64 and counting...]
"How can you see into my eyes like open doors leading you down into my core, where I've become so numb? Without a soul, my spirit sleeping somewhere cold, until you find it there and lead it back home."

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Tuesday, April 8, 2003 2:12 PM
Really, they are all happy about having the world's fastest elevator. Frankly, who cares?

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Im cold......

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Tuesday, April 8, 2003 2:32 PM
yeah what does the world's fastest elevator have to do with TTD
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Tuesday, April 8, 2003 3:38 PM
BTW, I heard that the proposed worlds tallest building slated to be built in Shanghai is on hold until the plans for the new World trade Center is finalized. Ofcourse it has nothing to do with this topic, but just goes to show the lengths people go for bragging rights.

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Krimson n' Kream, Spr 98

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Tuesday, April 8, 2003 5:12 PM
...and the coaster connection is?
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If you have a problem with clones, the solution is real simple—Stop traveling.
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