Monday, March 10, 2014 1:17 PM

The New Texas Giant is going up the lift hill. When it is cresting the top, however, a screw from the lapbar falls out from a height of 147 feet (heh heh). Each time the screw hits the ground, it bounces up 3/4 of the vertical distance covered on the previous bounce. Given that the screw keeps bouncing until it stops, how much distance does it cover?

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Monday, March 10, 2014 1:45 PM

Nothing in the problem statement suggests that it will actually stop bouncing, but the bounces will get small enough as to converge on a number:

1029 ft.

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Monday, March 10, 2014 4:21 PM

False. The screw gets fired because it has a problem using the thumbprint scanners.

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Monday, March 10, 2014 7:36 PM

"I'd rather die and take everybody with me than sit here one more minute and listen to these idiots talk about bouncing!" - bender rodriguez

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Monday, March 10, 2014 8:10 PM

Fine. Six Flags Over Texas gets a new screw and Michigan's Adventure gets nothing again.

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Monday, March 10, 2014 8:52 PM

Well if you are talking about the Euclidean distance, it would be infinite to an asymptote of 147 feet. The better question is where do I buy a screw that can drop from 147 feet and bound back over 110 feet, the applications are endless.

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Monday, March 10, 2014 11:23 PM

I still have the following questions:

1) Was the screw coming loose the fault of Six Flags or the manufacturer?
2) Who will sue who?
3) Was Intamin the manufacturer, and if so, how did all the other screws stay in?

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Tuesday, March 11, 2014 7:16 AM

Agreed with Bakeman. The problem is the sum of an infinite geometric series...actually two.

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Wednesday, March 12, 2014 1:46 AM

Forty-two.

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Wednesday, March 12, 2014 6:32 PM

You can solve it by two infinite geometric series or by a system of equations. As for the manufacturer details, just pretend like it was the real NTaG I guess. :P

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Thursday, March 13, 2014 3:09 PM

I guess John Bender was right: the world is an imperfect place.

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