# How does Monte work?

Saturday, October 13, 2001 6:09 PM
Montezuma's Revenge.  How do these type of shuttles work?  I have always seen them blast through the loops but then what happens?  I've seen in pictures that there is track right behind the station that the train runs on.  Does that have anything to do with the rest of the ride?
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"I'm eccentric, I can do whatever I want"- Rat Race
*** This post was edited by CHOCOLATE STARFISH on 10/13/2001. ***
*** This post was edited by CHOCOLATE STARFISH on 10/13/2001. ***

*** This post was edited by Chitown on 10/14/2001. ***

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Saturday, October 13, 2001 6:17 PM
The train is launched foward by a flyweel system, goes through the loop, up the tower, and travels backwards back to the station. Rushes through the station and up the back tower before stopping at the station.
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Saturday, October 13, 2001 6:21 PM
P>hhhhh- now I feel really dumb.  Thanks.STRNG>FNT face=Verdana color=#ffffff size=2>SquishyMon/STRNG>/P>
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"I'm eccentric, I can do whatever I want"- Rat Race
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Saturday, October 13, 2001 7:50 PM
It's fairly simple; let me see if I can simplify it enough for CoasterBuzz even though I've never seen the system in person. :)
The train is really heavy...let's say a half-ton per car, plus another half-ton of passengers per car, for a total of about 7 tons (14,000 lbs.) for a 7-car train. Say we want to accelerate that train to 60 mph, that would be 88 ft/sec. Let's say we want to accelerate to full speed in 4 seconds. That means we need to accelerate 14,000 pounds to 88 feet/sec in 4 seconds. Let's see...that's 88 ft/sec / 4 sec = 22 ft/sec/sec. * 14,000 lbs = 308,000 ft-lbs/sec for 4 sec. If I did the math right, that would be about 560 HP for four seconds...at high efficiency, that would require about 418 kW of power to operate.
Now, there ought to be a more efficient way to do this than to use a 560-HP motor to pull the train. Particularly since that kind of energy is only needed for a few seconds. Why not store energy over a longer period of time when the train isn't moving, and let it all loose at once when it comes time to launch the train?
That's what the launch system on Montezooma does. A multi-ton flywheel is rotated to high speed. The flywheel is heavy so that it can hold lots of mechanical energy. A wire rope is connected to a pulley which is attached to the flywheel by means of a pneumatic clutch. The wire rope is attached to a pusher mechanism that comes up behind the train. The flywheel spins up to full speed, driven by a small electric motor (it takes longer than it takes to launch the train, but that's OK so long as it reaches full speed before launchtime) and the clutch is engaged. This puts the full rotating inertia of the flywheel into pulling the wire rope and thus pushing the train out of the station.
The train flies out of the station, the clutch releases, and the flywheel is brought back up to speed for the next launch.

Make sense, I hope?

--Dave Althoff, Jr.
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Saturday, October 13, 2001 7:55 PM
Hey Dave...maybe next year we can ride Viper at PPP...probably not;-)!
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Son of Drop Zone - PKI CoasterCamp I Champions!!!
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Saturday, October 13, 2001 8:26 PM
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DEJA VUE KICKS ALL FORMS OF BUTT!!!!
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Saturday, October 13, 2001 9:12 PM
Dave:

I'm afraid that our confusing English measurement system caught up with you.  Remember that a pound is actually a unit of force not mass

To accelerate a 14,000 lb train at 22 ft/sec^2 requires a thrust of  (22 ft/sec^2 / 32.2 ft/sec^2) * 14,000 lbs = 9565 lbs.  ( 32.2 ft/sec^2 is the acceleration of gravity which causes the mass of the train to weigh 14,000 lbs)  The power required varies as the speed increases.  At the end of the acceleration the power required is 88 ft/sec * 9565 lbs = 841,720 ft-lbs/sec = 1530 HP.

This of course just makes the need for some sort of energy storage system greater.

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