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The Coaster Mainframe: Coaster media for all!

http://www.crosswinds.net/~coastermainframe/

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Webmaster - G-Screams

http://gscreams.cjb.net

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Ride with full

http://www.experiencethepoint.com

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Kerry - Bright Man of the Elite Eight

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Ride with full

http://www.experiencethepoint.com

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It takes about 22 seconds to get up the lift of Millennium Force. Thats really quite fast compared to other lifts.

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A New World. A New Technology. One Last Hope for Salvation. Neon Genesis Evangelion

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Kerry - Bright Man of the Elite Eight

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Ride with full

http://www.experiencethepoint.com *** This post was edited by Andrew on 7/9/2001. ***

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Kerry - Bright Man of the Elite Eight

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The Vector of the first drop is mostly a curve. If you paid attention in Physics class, you learned that a roller coaster will only gain or lose energy and momemtum on a curve, not vertical. MF has a drop approaching vertical, but not quite. So if you look at the drop, most of it is a parabolic curve. Thus, there is more of a curve, which means faster speeds. If they cranked the lift speed to only 16 MPH, then they could easily shatter ST2K's record for speed. Hope this helped out!

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Ride with full

http://www.experiencethepoint.com

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Did you realize that Theme Park Nacho cheese isn't really cheese?

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Objects falling near the earth's surface tend to accelerate at a rate of about 32 ft/sec/sec. With this bit of information, you can take indefinite integrals and get:

a = 32 ft/sec/sec.

v = 32t + v0 feet/second

d = 16t^2 + v0t + d0 feet

If we assume that d0=0 (we're falling the whole distance) and v0=0 (we're falling from a dead stop) we can reduce the equations as follows:

a = 32 ft/sec/sec

v = 32t ft/sec

d = 16t^2 feet

If we know the distance (310 feet, for instance) we can solve for time:

d = 16t^2 feet

d/16 = t^2

sqr(d)/4 = t

And we can substitute that expression for t in the velocity equation:

v = 32t feet/second

v = 32 * (sqr(d)/4) feet/second

We can do one more conversion because 1 mph is equal to 5280 feet per 3600 seconds:

v = (3600/5280) * 32 * (sqr(d)/4) miles/hour

If you reduce all the fractions you end up with:

V [mph] = 60/11 * sqr (d [feet])

For a 310 foot drop, this works out to 96.037 mph.

It is reasonable to expect that the formula will give a higher number than reality, because the formula represents an ideal case, where there are no resistive forces (friction, wind resistance, etc.). But it will get you into the ballpark for most rides. It also fails to take into consideration the initial velocity which, on Millennium Force, is 22 ft/sec. I didn't manage to work that one out because when v0 is non-zero, the equations get complicated:

a = 32 ft/sec/sec

v = 32t + v0 ft/sec

d = 16t^2 + v0t feet

This means that the time required is now a quadratic polynomial and I always hated solving those. I got as far as...

310 = 16t^2 + 22t

155 = 8t^2 + 11t

155 = t(8t+11)

If anybody wants to solve that one for t, then you can plug it into...

v = 32t + 22 ft/sec

then multiply by 3600/5280 to get the ideal maximum speed that Millennium Force can possibly attain in an ideal world.

So if you read that you will find out gravity doesn't allow... Also please don't call me a idiot

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Andrew

http://www.experiencethepoint.com

*** This post was edited by Andrew on 7/9/2001. ***

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SFGAm Trip - July 13-17, 2001

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An easy way to look at it is that only some of the drop is actually 80 degrees!! MF has one of the most rounded accent and decent on a drop of any coaster.

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Kerry - Bright Man of the Elite Eight

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CDNSN

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Robodud said:

"Joe, What brakes?? If they shut off the brakes you'd have trains colliding in the station. There are no midcourse brakes throughout the ride."

I was only repeating what I was told. Obviously, I was misinformed ! :) Sorry.

As for me being too stupid to notice the lack of brakes...I've only ridden it twice. I didn't notice any brakes, but I didn't notice any lack of brakes either. Considering that the end brakes were magnetic, I suppose I could have thought that they were smooth enough to be unnoticeable. I know...I'm grasping at straws. ;) Sorry again for the dumb/incorrect post.

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