I have been hearing rumors that they maybe speeding up the elevetor lift on Millennium Force to make it go over the 100mph would that make Millennium Force the tallest & faster than Steel Dragon 2000 because the dragon has a chain lift? What's the speed on Millennium Force elevator lift right now?
well it would definitely make it faster than SD2K but not taller. they could make it taller by counting the inches the car raises up when it goes over the lift at a faster speed. it would be cool if they did do that. but i doubt it that they will.
It speeds up every time... As soon as the brakes at the end of the ride are clear thee lift speeds up. The speed is 13 miles per hour. I do belive there is a maximum speed of the lift but I am not sure.
The lift speeds up to it's max speed when the incoming train exits the block breaks into the station. It usually happens about half way up. There is a point at which the lift will stop if the train has not entered the stations yet. The lift speed is 13 mph, 20 ft per second.
------------- Kerry - Bright Man of the Elite Eight
The record will still belong to another coaster: Dodonpa of Japan. Scheduled to open on the 22, it will go 106 mph. It is no use, Cedar Point will not regain the speed or height record for a while, sorry:(
It takes about 22 seconds to get up the lift of Millennium Force. Thats really quite fast compared to other lifts.
------------- A New World. A New Technology. One Last Hope for Salvation. Neon Genesis Evangelion
Can't confirm that it's true or not, but when I was there on July 3rd, I hung out with an off duty ride op. He said that last time they had an after hours employee ride session, that thye turned off the brakes, and clocked MF at 106 mph. It could be true...but who knows ?
Well, it is possible. Gravity has nothing to do with it, it has to do with Vectors. The wheels are large enough to allow a 97MPH rotation. S:TE has very large wheels due to rapid acceleration. MF doesn't have such rapid acceleration so the wheels are ok. The Vector of the first drop is mostly a curve. If you paid attention in Physics class, you learned that a roller coaster will only gain or lose energy and momemtum on a curve, not vertical. MF has a drop approaching vertical, but not quite. So if you look at the drop, most of it is a parabolic curve. Thus, there is more of a curve, which means faster speeds. If they cranked the lift speed to only 16 MPH, then they could easily shatter ST2K's record for speed. Hope this helped out!
It is not possible for Millennium Force to go faster than 95 mph due to height and gravity just doesn't allow. The only way for the ride to go faster if they speed up the lift that just won't happen... the ride sets up enough as it is...
You sound like a idiot saying "Gravity Won't Allow"! I wrote a whole physics thing explaining how it can work! Go to physics class, then see if I am right... ------------- ------------------------- Did you realize that Theme Park Nacho cheese isn't really cheese?
Read what RideMan said over at GTTP(http://www.guidetothepoint.com/thepoint/cpplace/thread.asp?ForumID=2&TopicID=1783):
Objects falling near the earth's surface tend to accelerate at a rate of about 32 ft/sec/sec. With this bit of information, you can take indefinite integrals and get:
a = 32 ft/sec/sec. v = 32t + v0 feet/second d = 16t^2 + v0t + d0 feet
If we assume that d0=0 (we're falling the whole distance) and v0=0 (we're falling from a dead stop) we can reduce the equations as follows:
a = 32 ft/sec/sec v = 32t ft/sec d = 16t^2 feet
If we know the distance (310 feet, for instance) we can solve for time:
d = 16t^2 feet d/16 = t^2 sqr(d)/4 = t
And we can substitute that expression for t in the velocity equation:
v = 32t feet/second v = 32 * (sqr(d)/4) feet/second
We can do one more conversion because 1 mph is equal to 5280 feet per 3600 seconds:
v = (3600/5280) * 32 * (sqr(d)/4) miles/hour
If you reduce all the fractions you end up with: V [mph] = 60/11 * sqr (d [feet])
For a 310 foot drop, this works out to 96.037 mph.
It is reasonable to expect that the formula will give a higher number than reality, because the formula represents an ideal case, where there are no resistive forces (friction, wind resistance, etc.). But it will get you into the ballpark for most rides. It also fails to take into consideration the initial velocity which, on Millennium Force, is 22 ft/sec. I didn't manage to work that one out because when v0 is non-zero, the equations get complicated:
a = 32 ft/sec/sec v = 32t + v0 ft/sec d = 16t^2 + v0t feet
This means that the time required is now a quadratic polynomial and I always hated solving those. I got as far as...
310 = 16t^2 + 22t 155 = 8t^2 + 11t 155 = t(8t+11)
If anybody wants to solve that one for t, then you can plug it into...
v = 32t + 22 ft/sec
then multiply by 3600/5280 to get the ideal maximum speed that Millennium Force can possibly attain in an ideal world.
So if you read that you will find out gravity doesn't allow... Also please don't call me a idiot
Thanks Andrew, Where is that site someone posted a while ago which explained how an object dropped straight down from that height with an initial velocity of 13 mph would only get to 95. That's not including MF's angles and stuff.
An easy way to look at it is that only some of the drop is actually 80 degrees!! MF has one of the most rounded accent and decent on a drop of any coaster.
------------- Kerry - Bright Man of the Elite Eight
"Joe, What brakes?? If they shut off the brakes you'd have trains colliding in the station. There are no midcourse brakes throughout the ride."
I was only repeating what I was told. Obviously, I was misinformed ! :) Sorry.
As for me being too stupid to notice the lack of brakes...I've only ridden it twice. I didn't notice any brakes, but I didn't notice any lack of brakes either. Considering that the end brakes were magnetic, I suppose I could have thought that they were smooth enough to be unnoticeable. I know...I'm grasping at straws. ;) Sorry again for the dumb/incorrect post.