*** This post was edited by Draco on 8/30/2001. ***
-------------
Mayday - Memorial Day Weekend - Nonpoint, Nickelback, Oleander, Staind
Ozzfest - June 8 - Papa Roach, Linkin Park, Disturbed, Black Sabbath
Awake Tour- June 15 - Darwin's Waiting Room, Puddle of Mudd, Deftones, Godsmack
I don't know if I missed something, but with a 300 foot drop the train goes 93, how are they getting 120 for something more than twice as tall?
-------------
http://www.ultimaterct.com for RCT
-----------------
Dave
-------------
"Roller Coaster favorite ride , let me kiss you one last time" Blink 182
-------------
NEW - 35 Michigan's Adventure Photos at G-Screams
http://gscreams.cjb.net
The reason a drop twice as high does not produce a speed twice as fast is that gravity accelerates objects based on the time that they fall, not based on the distance that they fall.
A 300 foot freefall results in a theoretical max of 94.5 mph after a 4.33 second drop... adding 300 feet to the drop brings the total drop time up to 6.12 seconds producing a theoretical max of 133.6 mph
-----------------
probie
Also, gatorwoodie... just a quick correction... the speed at the end of the first second is 32 ft/sec but the distance travelled during the first second is only 16 feet since the the coaster started out at 0 and only reached 32 ft/sec at the end of the second. During the fourth second, the car would start at 96 ft/sec and end at 128 ft/sec resulting in the car travelling 112 feet during the 4th second.
-----------------
probie
Clarkbar said:
Terminal Velocity. It is around a 128 mph I thought??? It's the speed limit at which things can fall.
Terminal velocity isn't a fixed number, though. It varies based on the wind resistance (friction with air) of the item in freefall. When the acceleration due to gravity is offset by the DEceleration due to friction, you've reached terminal velocity.
This is the whole reason a parachute works. A human body in freefall really doesn't present that much surface area, and plummets. When the skydiver (hopefully) opens his chute, a MUCH larger surface area is presented, and bingo -- a much lower "terminal velocity". (That's a simplification, since the chute actually "catches" air, but the principal is the same...)
-------------
--Greg
My page My other page And my coaster page
225.552m= .5*9.8*t^2
t^2 = 225.552m\.5*9.8
t= 6.78 seconds neglecting air resistance
v =gt
v= 9.8*6.78
v= 66.4 m/s or 148.5 mph (Not really worring about sig figs)
v^2 = 2gh (Another Formula produces exact same speed)
Let's keep this as simple as possible. I'm no physics genius (I am in AP Physics) but the proposed ride could easily have that height and velocity. Mass is insignificant because all bodies fall at the same rate. I do not know exactly how to fit air resistance and friction in the equations so I left them off. In conclusion, the maximum speed in a vaccum that a body can reach from 740ft. is 148.5 mph. Is'nt Physics wonderful?
Sorry, it's Friday again...
-----------------
Yeeee Haaawwww!
The ride is 740ft. But the drop isnt 740ft. the sketch shows a bridge-type construction over the street. Id say the ride would stay at least 40 ft from the ground. I dont know the specifics but the entire drop will not be 740ft.
-----------------
"ok everyone go ahead and pull down on your shoulder restraint so you feel nice and stuck!"
But S:TE generates it's zero gravity a different way, with the verticle climb, stall, then the reverse drop. So I was way off, but still a 6-7 second drop sounds totally wicked, don't think most people will be able to scream that long without running out of breath! Bring it on!
You must be logged in to post